這個點陣左移，曾經讓我......如今在朋友指導下.........主要部分在紅色部分，請大家理解那里就行了！會了也沒有什么！硬件：行采用74HC154＋S8550，列采用74HC595！
#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
#define LINE P0//定義行線IO口，即74HC154控制端
#define shudu 20//字移動的速度
sbit DATA=P1^4;//74HC595數據端
sbit CLK=P1^5;//74HC595移位脈沖端
sbit CLKR=P1^6;//74HC595數據鎖存端
uchar move;//移動幾位變量
uchar line;//行變量
uint word;//字節變量
uchar BUF[4];//4組緩存數組以便動態更改數據
uchar code table[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x10,0x3F,0xF8,0x04,0x10,0x04,0x14,0xFF,0xFE,0x04,0x10,0x04,0x10,
0x3F,0xF0,0x04,0x10,0x04,0x00,0x08,0x00,0x08,0x00,0x10,0x00,0x20,0x00,0x40,0x00,
0x01,0x00,0x01,0x08,0x7F,0xFC,0x01,0x00,0x3F,0xF8,0x01,0x00,0xFF,0xFE,0x00,0x10,
0x1F,0xF8,0x10,0x10,0x1F,0xF0,0x10,0x10,0x1F,0xF0,0x10,0x10,0x10,0x50,0x10,0x20,
0x01,0x10,0xFF,0x90,0x14,0x50,0x14,0x7C,0x7F,0x50,0x55,0x90,0x55,0x10,0x57,0xFE,
0x61,0x04,0x41,0x7E,0x41,0x44,0x7F,0x44,0x41,0x44,0x41,0x44,0x7F,0x7C,0x41,0x44,
0x00,0x78,0x3F,0x80,0x11,0x10,0x09,0x20,0x7F,0xFE,0x42,0x02,0x82,0x04,0x7F,0xF8,
0x04,0x00,0x07,0xF0,0x0A,0x20,0x09,0x40,0x10,0x80,0x11,0x60,0x22,0x1C,0x0C,0x08,
0x04,0x40,0x04,0x44,0xFF,0xFE,0x04,0x40,0x08,0x7C,0x09,0x44,0x7F,0xC4,0x08,0x7C,
0x0A,0x44,0x3F,0x44,0x22,0x7C,0x22,0x44,0x22,0x44,0x3E,0x44,0x22,0x94,0x01,0x08,
0x08,0x20,0x08,0x24,0xFF,0xFE,0x08,0x20,0x01,0x08,0x3F,0xFC,0x20,0x08,0x20,0x08,
0x3F,0xF8,0x20,0x08,0x20,0x00,0x20,0x00,0x20,0x00,0x40,0x00,0x40,0x00,0x80,0x00,
0x08,0x10,0x08,0x10,0x08,0x10,0x10,0x20,0x10,0x20,0x22,0x44,0x7E,0xFC,0x04,0x08,
0x08,0x10,0x10,0x20,0x20,0x40,0x7E,0xFC,0x00,0x00,0x00,0x04,0xFF,0xFE,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00
};//字模數組
/********************************/
/**74HC595移位寄存器送數子函數***/
/********************************/
void song(uchar z)//帶參數函數
{
uchar num,hang;//定義變量
hang=z;//將形參給變量
for(num=0;num<8;num++)//移動8次將數據發送完畢
{
if(hang&0x01==1)//將高7位屏蔽掉，保留最低位判斷
DATA=1;//為1就將74HC595數據端置1
else
DATA=0;//否則給0
CLK=0;//上升沿送走數據
CLK=1;//高電平形成上升沿
hang>>=1;//將數移走一位
}
}
/********************************/
/*裝一線數據子函數（即一行數據）*/
/********************************/
void yixian()
{
uchar s;
for(s=0;s<2;s++)/*循環2次，得到第1個字（代碼存在數組1與2中）
與第2個字（代碼存在數組2與3中）的某一行數值*/
{
BUF[s*2]=table[word+(32*s)+(line*2)];//左半屏代碼，line表示行數，word表示字數
BUF[s*2+1]=table[word+(32*s+1)+(line*2)];//右半屏代碼
}
}
/********************************/
/*將一行數據轉換出來，然后顯示*/
/********************************/
void yipai()
{
uchar temp,yi;
if(move<8)//處理移動次數小于8次的部分
{
yi=move;
temp=(BUF[1]<<yi)|(BUF[2]>>(8-yi));/*將第1個字的右半屏數左移yi次，
然后或上第2個字左半屏的8-yi次數,注此句是處理右半屏的數*/
song(~temp);//發送給74HC595
temp=(BUF[0]<<yi)|(BUF[1]>>(8-yi));/*將第1個字的左半屏數左移yi次，
然后或上第1個字右半屏的8-yi次數,注此句是處理左半屏的數*/
song(~temp);//發送給74HC595
}
else//處理移動次數小于8次以外的部分
{
yi=move-8;
temp=(BUF[2]<<yi)|(BUF[3]>>(8-yi));//原理同上
song(~temp);//發送給74HC595
temp=(BUF[1]<<yi)|(BUF[2]>>(8-yi));//原理同上
song(~temp);//發送給74HC595
}
}
void zou()
{
uchar i;
while(word<256)
{
for(move=0;move<16;move++)//要移多少位？
{
for(i=0;i<shudu;i++)//一字移動的速度
{
for(line=0;line<16;line++)//掃描16次，即完成一個字的移動
{
yixian();//調用一線子程序
yipai();//調用數據轉換子程序
LINE=line;//打開行線，即174HC154行線端
CLKR=1;//在74HC595處鎖存起來
CLKR=0;
CLKR=1;
}
}
}
word=word+32;//一個字顯示完了，就顯示下一個字
}
word=0;//清0重新開始
}
/********************************/
/************主程序*************/
/********************************/
void main()
{
while(1)
{
zou();
}
}
視頻祥見：http://www.tudou.com/programs/view/D0SCJyO4RBQ/